The SSA ambiguous case shows both triangles. When two sides and a non-included angle can form two different triangles, this solver lists both instead of quietly picking one. Try side a = 7, side b = 10, angle A = 30°.
Enter any 3 values (1 must be a side)
opposite angle A
opposite angle B
opposite angle C
opposite side a
opposite side b
opposite side c
Solved case
SSA (ambiguous — two triangles)
Two different triangles satisfy these values. Both are shown below — swinging side b left or right joins side c in two places. Most free calculators show only one of them.
Triangle 1 of 2
Side a
7
Side b
10
Side c
13.5592
Angle A
30°
Angle B
45.5847°
Angle C
104.4153°
Area (sq units)
33.8981
Perimeter (units)
30.5592
| Quantity | To a | To b | To c |
|---|---|---|---|
| Altitude (units) | 9.6852 | 6.7796 | 5 |
| Median (units) | 11.3876 | 9.5617 | 5.342 |
Inradius r (units)
2.2185
Circumradius R (units)
7
By angle
Obtuse
By sides
Scalene
Step-by-step working
- Case SSA — ambiguous, this is triangle 1 of 2. Start with the law of sines.
- sin B / b = sin A / a → sin B = 10 × sin 30° / 7 = 0.7143
- arcsin gives 45.5847°, and 180° − 45.5847° = 134.4153° has the same sine. Both keep the angle sum under 180°, so both are real triangles.
- Here B = 45.5847°, so the third angle = 180° − 30° − 45.5847° = 104.4153°
- Law of sines again: c = a · sin(third angle) / sin A = 13.5592
Triangle 2 of 2
Side a
7
Side b
10
Side c
3.7613
Angle A
30°
Angle B
134.4153°
Angle C
15.5847°
Area (sq units)
9.4032
Perimeter (units)
20.7613
| Quantity | To a | To b | To c |
|---|---|---|---|
| Altitude (units) | 2.6866 | 1.8806 | 5 |
| Median (units) | 6.695 | 2.5639 | 8.424 |
Inradius r (units)
0.9058
Circumradius R (units)
7
By angle
Obtuse
By sides
Scalene
Step-by-step working
- Case SSA — ambiguous, this is triangle 2 of 2. Start with the law of sines.
- sin B / b = sin A / a → sin B = 10 × sin 30° / 7 = 0.7143
- arcsin gives 45.5847°, and 180° − 45.5847° = 134.4153° has the same sine. Both keep the angle sum under 180°, so both are real triangles.
- Here B = 134.4153°, so the third angle = 180° − 30° − 134.4153° = 15.5847°
- Law of sines again: c = a · sin(third angle) / sin A = 3.7613
Methods follow the law of cosines and law of sines as stated on Wolfram MathWorld, Heron's formula for area, and the ambiguous-case treatment taught by Math is Fun. Lengths are unit-agnostic — enter all sides in the same unit and areas come out in that unit squared.
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